amk/n(n-1)

[chrisheaven]

will amk be posting in this thread-
I guess so

 

[amk714]

Hey, what's the big idea? You can't divide my initials by an unknown quantity. Mathematical pervert!

 

[chrisheaven]

correction
a/mk=(a=b)(a-b)
or is that a^2-b^2?

 

[leafstk]

Mils may know the answer 😀 😛

 

[milagros317]

n(n-1) = P(n,2)

At least that equation is true. 😀

 

[chrisheaven]

n(n-1) = P(n,2)

At least that equation is true. 😀

at least??
have you considered the old German motto
"Quid est veritas?"

 

[milagros317]

I have considered that C(n,2) = P(n,2)/2! = n(n-1)/2

 

[isabeau]

Hey, what's the big idea? You can't divide my initials by an unknown quantity. Mathematical pervert!

ack dont mention math *shudders* and hiiii amk so glad to see you have a thread can i tease you now?

isabeau

 

[milagros317]

Go ahead, Isabeau, he will like it. 😀

 

[amk714]

ack dont mention math *shudders* and hiiii amk so glad to see you have a thread can i tease you now?

isabeau

Of course you can tease me! Just like I can tease you (and not just by mentioning math, I have other ways of making you shudder).

 

[milagros317]

So I shouldn't mention that C(n,3) = n(n-1)(n-2)/6, Isabeau? 😀

 

[TKpervert]

Hey, what's the big idea? You can't divide my initials by an unknown quantity. Mathematical pervert!

Try to be a tad more judicious with the cavalier use of the term 'pervert', if that's ok.

 

[amk714]

Sorry TKpervert, I wasn't referring to you. But next time I won't use that term. What about "deviant," is that all right? 😛

 

[TKpervert]

Yeah, 'deviant' is cool. Unfortunately it fits too.
Actually you can call me anything you want, just don't call me late for dinner.

 

[chrisheaven]

1/2n(n-1) should give you SUM idea

 

[amk714]

Well, if that's the SUM, then what's the DIFFERENCE?

 

[chrisheaven]

difference is
a-mk/12/n(n-1)

 

[milagros317]

(24 x Chris)/n(n-1)(n-2)(n-3) = 4way combination fool

 

[chrisheaven]

(24 x Chris)/n(n-1)(n-2)(n-3) = 4-way combination fool

you mean 4way not 4-way , I suspect, Mils
lol

 

[milagros317]

Yes, thanks for the correction, I have edited. 😀

 

[chrisheaven]

Yes, thanks for the correction, I have edited. 😀

Mon plaisir, mein Senor

 

[milagros317]

On the other hand, I believe that

(120xChris)/n(n-1)(n-2)(n-3)(n-4) = 5way combination fool

😛

 

[chrisheaven]

On the other hand, I believe that

(120xChris)/n(n-1)(n-2)(n-3)(n-4) = 5way combination fool

😛

you believe......or do you know?

 

[milagros317]

Now I'm sure. 😀

(120xChris)/n(n-1)(n-2)(n-3)(n-4) = 5way combination fool

 

[amk714]

(chrisheaven)^(nth power) = n-fool function f👎