math puzzle

[milagros317]

Each of the letters A through I represents a different digit 1 through 9.

A/BC + D/EF + G/HI = 1

As you can see, each fraction has a one-digit numerator and a two-digit denominator.
I know of only one solution (up to changing the order of the addition). I would be glad to see another.
My solution is below.
X
X
X
X
X
X
X
X
X
X
X
X
X
X
X
X
X
X
X
X
X
X
X
X
X
X
X
X
X
X
X
X
X
X
X

9/12 + 5/34 + 7/68 = 1

Changing the order of the addition is not a different solution.

5/34 + 9/12 + 7/68 = 1

 

[DeanGrimes7]

If you assume that the denominators are actually the product of two single-digit numbers you can use the formula below to realise the answer

1/(3*6) + 5/(8*9) + 7/(2*4) = 1

It's a round about way to get it, so I presume is correct

 

[milagros317]

If you assume that the denominators are actually the product of two single-digit numbers you can use the formula below to realise the answer

1/(3*6) + 5/(8*9) + 7/(2*4) = 1

It's a round about way to get it, so I presume is correct

That is a correct solution to a different puzzle, namely:

A/B*C + D/E*F + G/H*I = 1